[每日LeetCode] 26. Remove Duplicates from Sorted Array

  |   0 评论   |   687 浏览

Description:

Given a sorted array nums , remove the duplicates in-place such that each element appear only_once_and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array [in-place] (https://en.wikipedia.org/wiki/In-place_algorithm) with O(1) extra memory.

Example 1:

Given nums = [1,1,2],

Your function should return length =  2, with the first two elements of nums being 1 and 2 respectively.

It doesn't matter what you leave beyond the returned length.

Example 2:

Given nums = [0,0,1,1,1,2,2,3,3,4],

Your function should return length = 5, with the first five elements of nums being modified to 0, 1, 2, 3 and 4 respectively.

It doesn't matter what values are set beyond the returned length.

思路:本题要求去除已排序数组中重复的元素,并返回数组大小。考虑从前往后找,找到一个和前一个数字不同的就放到前面,相同的话不予处理。


C++代码

class Solution {
public:
     int removeDuplicates(vector<int>& nums) {
        if(nums.size()==0) return 0;
        int len = 1;
        for(int i=1;i<nums.size();i++){
            
            if(nums[i]!=nums[i-1]){
                nums[len++] = nums[i];
            }
        }
        return len;
    }
};

运行时间:32ms
运行内存:10.7M

评论

发表评论